# Establishing the relation between loss in weight of a solid when fully immersed in tap water and salty water with the weight of water displaced

**Aim**

### To establish the relationship between the loss in weight of solid when fully immersed in

(i) tap water

(ii) strongly salty water,

with the wait of water displaced by it by taking at least two different solids.

**Apparatus Required**

spring balance, two small different (metallic) solid bodies, eureka can, measuring cylinder, a strong thread, tap water and strongly salted water of known densities.

**Theory**

According to Archimedes’ principle, when a body is partially or wholly immersed in a fluid, it experiences an upthrust [buoyant force] equal to the weight of the fluid displaced by the immersed part of the body. This upthrust is equal to the apparent loss in weight of the body.

**Upthrust (buoyant force) = Weight of the liquid displaced** **= Loss in weight of the body**

## **Procedure**

- Find the zero error and least count of the spring balance.
- Take one of the two given solids ( say a brass bob). Suspend it by a thin thread from the hook of a spring balance.
- Note the weight of solid from spring balance in air.
- Now take a eureka can and fill it with tap water upto its spout.
- Place a measuring cylinder below the spot of eureka can.
- Now immerse the solid gently into the water of the eureka can. The water displaced by its gets collected in the measuring cylinder.
- When water stops dripping through the spout, note the weight of the solid and the volume of water collected in the measuring cylinder.
- Take some tap water in a beaker. Add to it sufficient salt. stir it with a glass rod. If it dissolves, add more salt. In this way, prepare a nearly saturated solution of salt in water. Now fill the eureka can with this strongly salted water.
- Repeat the steps 5,6 and 7.
- Take the second solid ( different from first ) and repeat the above experiment.

**Observations**

Least count of the spring balance = 5 gf

Zero error in the spring balance = *±* 0 gf

S. No. | Weight of solid in air, w_{1} (gf) | Weight of solid in tap water, w_{2} (gf) | Weight of solid in salty water, w_{3} (gf) | Loss in weight in tap water, w_{1}-w_{2} (gf) | Loss in weight in salty water,w_{1}-w_{2} (gf) |

1. | 60 | 50 | 48 | 10 | 12 |

2. | 35 | 30 | 24 | 5 | 6 |

S. No. | Volume of tap water collected (ml) | Volume of salty water collected (ml) | Mass of tap water collected (g) | Mass of salty water collected (g) | Weight of tap water collected (gf) | Weight of salty water collected (gf) |

1. | 10 | 10 | 10 | 12 | 10 | 12 |

2. | 5 | 5 | 5 | 6 | 5 | 6 |

**Result**

Since density of tap water is 1g cm^{-3}, the volume of water collected in the measuring cylinder gives the mass of water displaced by the solid, when it is completely immersed in water. It is found that this is equal to the difference in weight of solid in air and in water i.e., the loss in weight of solid.

i.e., Loss in weight of solid (gf) = Weight of water displaced (gf) = Volume of water displaced (cm³)

This is true in case of both the cases i.e. tap water and strongly salty water. This verifies the Archimedes’ principle.

However, in case of strongly salted water, it is found that loss in weight of solid is much more than the volume of salty water displaced. This indicates that density of salty water is more than density of tap water.

**Precautions**

- The concave surface reading of liquid should be taken parallel to eye from measuring cylinder.
- The solid should not touch the sides or bottom of the cylinder.
- The solid should be completely immersed in liquid.
- While taking the reading of measuring cylinder, keep your eye in horizontal plane with liquid level.

## Comments

## Riya

Nice

## himaja

thanks

## Jeel Kateliya

Ok

## Rahul Singh Rajput

Mind blowing good

## Prince Kumar

Mind blowing sir

## Kousalya

Thanks you so much I understand very easily